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DSSSB PRT/TGT Permutation & Combination Questions with Answers & Explanations

20 Permutation & Combination questions from the Subject: Mathematics section of DSSSB PRT/TGT, each with the correct answer and a worked explanation. Try each question first, then tap Show answer to check. When you're ready, take the timed chapter-wise test to see your all-India rank.

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Question 1

In how many ways can a committee of 2 be chosen from 11 people?

  1. A66
  2. B110
  3. C22
  4. D55
Show answer
Answer: (D) 55 ⁿCᵣ = 11C2 = 55.
Question 2

In how many ways can a committee of 4 be chosen from 8 people?

  1. A32
  2. B78
  3. C70
  4. D140
Show answer
Answer: (C) 70 ⁿCᵣ = 8C4 = 70.
Question 3

In how many ways can a committee of 3 be chosen from 8 people?

  1. A24
  2. B56
  3. C336
  4. D112
Show answer
Answer: (B) 56 ⁿCᵣ = 8C3 = 56.
Question 4

In how many ways can a committee of 3 be chosen from 7 people?

  1. A70
  2. B21
  3. C35
  4. D210
Show answer
Answer: (C) 35 ⁿCᵣ = 7C3 = 35.
Question 5

In how many ways can a committee of 4 be chosen from 8 people?

  1. A32
  2. B70
  3. C78
  4. D140
Show answer
Answer: (B) 70 ⁿCᵣ = 8C4 = 70.
Question 6

In how many ways can a committee of 4 be chosen from 6 people?

  1. A30
  2. B15
  3. C360
  4. D24
Show answer
Answer: (B) 15 ⁿCᵣ = 6C4 = 15.
Question 7

In how many ways can a committee of 2 be chosen from 11 people?

  1. A110
  2. B66
  3. C55
  4. D22
Show answer
Answer: (C) 55 ⁿCᵣ = 11C2 = 55.
Question 8

In how many ways can a committee of 4 be chosen from 10 people?

  1. A220
  2. B420
  3. C210
  4. D5040
Show answer
Answer: (C) 210 ⁿCᵣ = 10C4 = 210.
Question 9

In how many ways can a committee of 3 be chosen from 6 people?

  1. A18
  2. B40
  3. C26
  4. D20
Show answer
Answer: (D) 20 ⁿCᵣ = 6C3 = 20.
Question 10

In how many ways can a committee of 2 be chosen from 6 people?

  1. A12
  2. B21
  3. C30
  4. D15
Show answer
Answer: (D) 15 ⁿCᵣ = 6C2 = 15.

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Question 11

In how many ways can a committee of 3 be chosen from 10 people?

  1. A240
  2. B130
  3. C720
  4. D120
Show answer
Answer: (D) 120 ⁿCᵣ = 10C3 = 120.
Question 12

In how many ways can a committee of 4 be chosen from 11 people?

  1. A660
  2. B330
  3. C7920
  4. D341
Show answer
Answer: (B) 330 ⁿCᵣ = 11C4 = 330.
Question 13

In how many ways can a committee of 3 be chosen from 9 people?

  1. A84
  2. B504
  3. C27
  4. D93
Show answer
Answer: (A) 84 ⁿCᵣ = 9C3 = 84.
Question 14

In how many ways can a committee of 4 be chosen from 12 people?

  1. A11880
  2. B507
  3. C990
  4. D495
Show answer
Answer: (D) 495 ⁿCᵣ = 12C4 = 495.
Question 15

In how many ways can a committee of 2 be chosen from 8 people?

  1. A36
  2. B56
  3. C28
  4. D16
Show answer
Answer: (C) 28 ⁿCᵣ = 8C2 = 28.
Question 16

In how many ways can a committee of 2 be chosen from 7 people?

  1. A21
  2. B14
  3. C42
  4. D28
Show answer
Answer: (A) 21 ⁿCᵣ = 7C2 = 21.
Question 17

In how many ways can a committee of 3 be chosen from 12 people?

  1. A220
  2. B1320
  3. C440
  4. D36
Show answer
Answer: (A) 220 ⁿCᵣ = 12C3 = 220.
Question 18

In how many ways can a committee of 2 be chosen from 10 people?

  1. A55
  2. B90
  3. C20
  4. D45
Show answer
Answer: (D) 45 ⁿCᵣ = 10C2 = 45.
Question 19

In how many ways can a committee of 4 be chosen from 11 people?

  1. A44
  2. B7920
  3. C330
  4. D660
Show answer
Answer: (C) 330 ⁿCᵣ = 11C4 = 330.
Question 20

In how many ways can a committee of 2 be chosen from 7 people?

  1. A42
  2. B21
  3. C14
  4. D28
Show answer
Answer: (B) 21 ⁿCᵣ = 7C2 = 21.

These are RankerClub practice questions written in the DSSSB PRT/TGT pattern. They are not official SSC/IBPS/RRB papers.

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